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Lesson 7.4

Triangles Worth Remembering

Focus: 45-45-90 derived from isosceles structure — 30-60-90 derived from equilateral triangle — exact values — Pythagorean Identity

The central goal of this lesson is for students to derive exact trig values for 30°, 45°, and 60° through geometric proof — not as facts to be handed down, but as logical necessities they can reconstruct at any time. A student who has proved these values is in a different epistemic position from one who has memorized them. They can reconstruct them if they forget. They understand that mathematics sometimes delivers perfect answers.

 

The 45-45-90 derivation is nearly inevitable once students recognize the isosceles structure. Most groups in Year 1 labeled the legs x and x and the hypotenuse c. A prompt — ‘do you know any famous equations that relate the sides of a right triangle?’ — moved most groups to the Pythagorean theorem and the result x√2 for the hypotenuse.

 

Rationalizing the denominator comes up immediately when a group is given the hypotenuse and asked for a leg. Many students in Year 1 had never encountered the concept. The right response is mini-sessions: gather two or three groups simultaneously, explain, give practice problems, and confirm understanding before moving on. Do not slow the whole class for a concept only some groups need yet.

 

For the 30-60-90: give one hint after five minutes of genuine struggle — start with an equilateral triangle. Students who receive this hint quickly see the altitude splits the base exactly in half. Some will scale immediately: hypotenuse 2, short leg 1, avoiding the fractions. Both approaches are valid. Press for the justification: why does the altitude split the base in half? Push for the isosceles argument.

 

Watch for the algebra errors that appeared in Year 1 and will appear again: (b−x)² written as b²−x² is the most common. When it appears, write a numerical example on the board: ‘What is (10−3)²? Is it 10²−3²?’ Students self-correct immediately once they see it numerically. This error appears again in the derivation of the Law of Cosines in Lesson 7.7 — addressing it here reduces its impact there.

The Pythagorean Identity — a natural consolidation payoff

The Advanced CYU problem for this lesson asks students to show that sin²(30°) + cos²(30°) = 1 using exact values, then explain geometrically why this must be true for any acute angle. The geometric explanation: in a right triangle with hypotenuse 1, the legs are sinθ and cosθ. The Pythagorean theorem gives sin²θ + cos²θ = 1² = 1.

This is the Pythagorean Identity. It is a direct consequence of the Pythagorean theorem and the definitions of sine and cosine. Students who work through this problem have proved a fundamental identity — not by manipulation, but by geometric argument. It is a small but satisfying moment of the course’s logical chain arriving at a result students will see again in precalculus.

Downloads for Lesson 7.4 
Lesson Plan

Download the full Lesson plan (tasks, timing, and teacher notes).

CYU Problems

Download the Check Your Understanding problems for the Lesson.

Student Note Sheets

Download the student note sheets for the Lesson.

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