Lesson 7.4
Triangles Worth Remembering
Focus: 45-45-90 derived from isosceles structure — 30-60-90 derived from equilateral triangle — exact values — Pythagorean Identity
The central goal of this lesson is for students to derive exact trig values for 30°, 45°, and 60° through geometric proof — not as facts to be handed down, but as logical necessities they can reconstruct at any time. A student who has proved these values is in a different epistemic position from one who has memorized them. They can reconstruct them if they forget. They understand that mathematics sometimes delivers perfect answers.
The 45-45-90 derivation is nearly inevitable once students recognize the isosceles structure. Most groups in Year 1 labeled the legs x and x and the hypotenuse c. A prompt — ‘do you know any famous equations that relate the sides of a right triangle?’ — moved most groups to the Pythagorean theorem and the result x√2 for the hypotenuse.
Rationalizing the denominator comes up immediately when a group is given the hypotenuse and asked for a leg. Many students in Year 1 had never encountered the concept. The right response is mini-sessions: gather two or three groups simultaneously, explain, give practice problems, and confirm understanding before moving on. Do not slow the whole class for a concept only some groups need yet.
For the 30-60-90: give one hint after five minutes of genuine struggle — start with an equilateral triangle. Students who receive this hint quickly see the altitude splits the base exactly in half. Some will scale immediately: hypotenuse 2, short leg 1, avoiding the fractions. Both approaches are valid. Press for the justification: why does the altitude split the base in half? Push for the isosceles argument.
Watch for the algebra errors that appeared in Year 1 and will appear again: (b−x)² written as b²−x² is the most common. When it appears, write a numerical example on the board: ‘What is (10−3)²? Is it 10²−3²?’ Students self-correct immediately once they see it numerically. This error appears again in the derivation of the Law of Cosines in Lesson 7.7 — addressing it here reduces its impact there.
The Pythagorean Identity — a natural consolidation payoff
The Advanced CYU problem for this lesson asks students to show that sin²(30°) + cos²(30°) = 1 using exact values, then explain geometrically why this must be true for any acute angle. The geometric explanation: in a right triangle with hypotenuse 1, the legs are sinθ and cosθ. The Pythagorean theorem gives sin²θ + cos²θ = 1² = 1.
This is the Pythagorean Identity. It is a direct consequence of the Pythagorean theorem and the definitions of sine and cosine. Students who work through this problem have proved a fundamental identity — not by manipulation, but by geometric argument. It is a small but satisfying moment of the course’s logical chain arriving at a result students will see again in precalculus.